To solve the equation \( x^2 + 2x = 3 \) using a function graph, we first rewrite the equation in standard form:
\[ x^2 + 2x - 3 = 0 \]
Next, we define a function based on this equation:
\[ f(x) = x^2 + 2x - 3 \]
To find the solutions to the equation \( f(x) = 0 \), we can graph the function \( f(x) \) and look for the x-intercepts, where the graph crosses the x-axis.
Steps to Create the Function Graph:
- Identify the function: \( f(x) = x^2 + 2x - 3 \)
- Find the vertex and the x-intercepts.
- Set the equation to zero and use factoring or the quadratic formula if necessary.
Finding the Roots:
To factor the quadratic equation \( x^2 + 2x - 3 \):
- We need two numbers that multiply to \(-3\) (the constant term) and add to \(2\) (the coefficient of \(x\)).
- The numbers \(3\) and \(-1\) satisfy this, so we can factor the equation: \[ (x + 3)(x - 1) = 0 \]
Setting Each Factor to Zero:
- \( x + 3 = 0 \) gives us \( x = -3 \)
- \( x - 1 = 0 \) gives us \( x = 1 \)
Summary of Solutions:
The roots of the equation \( x^2 + 2x - 3=0 \) are:
\[ x = -3 \quad \text{and} \quad x = 1 \]
Final Answer:
Thus, the solutions are:
x = −3, 1
So the correct response is:
x equals −3 comma 1