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Create a function graph to answer the question. Use the function graph to solve for the solutions to the equation x^2+2x=3 .(1...Asked by x
Create a function graph to answer the question. Use the function graph to solve for the solutions to the equation x^2+2x=3
.(1 point)
Responses
x=0,1
x equals 0 comma 1
x=2,0
x equals 2 comma 0
no solution
no solution
x=−3,1
.(1 point)
Responses
x=0,1
x equals 0 comma 1
x=2,0
x equals 2 comma 0
no solution
no solution
x=−3,1
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation \( x^2 + 2x = 3 \) using a function graph, we first rewrite the equation in standard form:
\[
x^2 + 2x - 3 = 0
\]
Next, we define a function based on this equation:
\[
f(x) = x^2 + 2x - 3
\]
To find the solutions to the equation \( f(x) = 0 \), we can graph the function \( f(x) \) and look for the x-intercepts, where the graph crosses the x-axis.
### Steps to Create the Function Graph:
1. Identify the function: \( f(x) = x^2 + 2x - 3 \)
2. Find the vertex and the x-intercepts.
3. Set the equation to zero and use factoring or the quadratic formula if necessary.
### Finding the Roots:
To factor the quadratic equation \( x^2 + 2x - 3 \):
1. We need two numbers that multiply to \(-3\) (the constant term) and add to \(2\) (the coefficient of \(x\)).
2. The numbers \(3\) and \(-1\) satisfy this, so we can factor the equation:
\[
(x + 3)(x - 1) = 0
\]
### Setting Each Factor to Zero:
1. \( x + 3 = 0 \) gives us \( x = -3 \)
2. \( x - 1 = 0 \) gives us \( x = 1 \)
### Summary of Solutions:
The roots of the equation \( x^2 + 2x - 3=0 \) are:
\[
x = -3 \quad \text{and} \quad x = 1
\]
### Final Answer:
Thus, the solutions are:
**x = −3, 1**
So the correct response is:
**x equals −3 comma 1**
\[
x^2 + 2x - 3 = 0
\]
Next, we define a function based on this equation:
\[
f(x) = x^2 + 2x - 3
\]
To find the solutions to the equation \( f(x) = 0 \), we can graph the function \( f(x) \) and look for the x-intercepts, where the graph crosses the x-axis.
### Steps to Create the Function Graph:
1. Identify the function: \( f(x) = x^2 + 2x - 3 \)
2. Find the vertex and the x-intercepts.
3. Set the equation to zero and use factoring or the quadratic formula if necessary.
### Finding the Roots:
To factor the quadratic equation \( x^2 + 2x - 3 \):
1. We need two numbers that multiply to \(-3\) (the constant term) and add to \(2\) (the coefficient of \(x\)).
2. The numbers \(3\) and \(-1\) satisfy this, so we can factor the equation:
\[
(x + 3)(x - 1) = 0
\]
### Setting Each Factor to Zero:
1. \( x + 3 = 0 \) gives us \( x = -3 \)
2. \( x - 1 = 0 \) gives us \( x = 1 \)
### Summary of Solutions:
The roots of the equation \( x^2 + 2x - 3=0 \) are:
\[
x = -3 \quad \text{and} \quad x = 1
\]
### Final Answer:
Thus, the solutions are:
**x = −3, 1**
So the correct response is:
**x equals −3 comma 1**
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