Asked by Ur m0m
create a equation from the 3 points (0,10),(1,10),(2,0)
Answers
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Answered by
GPT-4o mini
To create an equation from the three points \((0,10)\), \((1,10)\), and \((2,0)\), we can start by identifying the type of function that fits these points. Since we have three points, a quadratic function of the form \(y = ax^2 + bx + c\) could fit the data.
Let's denote the points as:
1. \((0, 10)\)
2. \((1, 10)\)
3. \((2, 0)\)
We can create a system of equations using these points.
1. From the point \((0, 10)\):
\[
c = 10
\]
2. From the point \((1, 10)\):
\[
a(1)^2 + b(1) + c = 10 \implies a + b + 10 = 10 \implies a + b = 0 \quad \text{(Equation 1)}
\]
3. From the point \((2, 0)\):
\[
a(2)^2 + b(2) + c = 0 \implies 4a + 2b + 10 = 0 \implies 4a + 2b = -10 \quad \text{(Equation 2)}
\]
Now we solve the system of equations.
From Equation 1:
\[
b = -a
\]
Substituting \(b = -a\) into Equation 2:
\[
4a + 2(-a) = -10 \implies 4a - 2a = -10 \implies 2a = -10 \implies a = -5
\]
Now substituting \(a = -5\) back into Equation 1 to find \(b\):
\[
-5 + b = 0 \implies b = 5
\]
Now we have \(a\), \(b\), and \(c\):
\[
a = -5, \quad b = 5, \quad c = 10
\]
Thus, the quadratic equation that fits the points \((0,10)\), \((1,10)\), and \((2,0)\) is:
\[
y = -5x^2 + 5x + 10
\]
This is the equation based on the given points.
Let's denote the points as:
1. \((0, 10)\)
2. \((1, 10)\)
3. \((2, 0)\)
We can create a system of equations using these points.
1. From the point \((0, 10)\):
\[
c = 10
\]
2. From the point \((1, 10)\):
\[
a(1)^2 + b(1) + c = 10 \implies a + b + 10 = 10 \implies a + b = 0 \quad \text{(Equation 1)}
\]
3. From the point \((2, 0)\):
\[
a(2)^2 + b(2) + c = 0 \implies 4a + 2b + 10 = 0 \implies 4a + 2b = -10 \quad \text{(Equation 2)}
\]
Now we solve the system of equations.
From Equation 1:
\[
b = -a
\]
Substituting \(b = -a\) into Equation 2:
\[
4a + 2(-a) = -10 \implies 4a - 2a = -10 \implies 2a = -10 \implies a = -5
\]
Now substituting \(a = -5\) back into Equation 1 to find \(b\):
\[
-5 + b = 0 \implies b = 5
\]
Now we have \(a\), \(b\), and \(c\):
\[
a = -5, \quad b = 5, \quad c = 10
\]
Thus, the quadratic equation that fits the points \((0,10)\), \((1,10)\), and \((2,0)\) is:
\[
y = -5x^2 + 5x + 10
\]
This is the equation based on the given points.
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