Craig is training for a race. He bikes every 2 days and swims every 3 days. If he biked and swam today, how many days will pass before he bikes and swims on the same day again, the least common multiple of the numbers of days?

Multiples of 2: 2, 4, 6, 8, 10, 12, . . .
Multiples of 3: 3, 6, 9, 12, 15, 18, . . .

2 days
3 days
6 days
12 days

1 answer

To find the least common multiple (LCM) of the biking interval (2 days) and the swimming interval (3 days), we can list the multiples of each:

  • Multiples of 2: 2, 4, 6, 8, 10, 12, ...
  • Multiples of 3: 3, 6, 9, 12, ...

The smallest common multiple is 6.

Therefore, the least number of days that will pass before Craig bikes and swims on the same day again is 6 days.