covert Joules/Kevin to

Question

(atm)(nm^3)/(K)

I have done this so far.

J*[1L atm]/[101.33J]*[(.001m)^3]/[1L]*[10^9n]/[1m]
Thank you

Answer 1

1 atm=101.3kPa
1 m=10^9nm

energy=X Pascals*1atm/0.1013Pa*Ym^3*(10^9nm/m)^3

energy=x*y*10^27/.1013 atm-nm^3/K