Bob Pursley answered this just a day or so ago but I can't find it or I would give you a link. Here is how to do it.
First you need to determine the limiting reagent.
H2 will require 100 kPa O2 to react completely; you have that much so H2 must be the limiting reagent. Next, you aren't given mols but you have P. In PV = nRT, T isn't given but it is constant, R is a constant, volume isn't given but it is constant. That means P is proportional to n; therefore, we can use kPa pressure as if it were mols.
.....2H2 + O2 ==> 2H2O
I....200...200.....0
C...-200..-100....+200
E.....0....100....200
So total P is 100 + 200 = ?kPa.
Could you show me where to start on solving this equation?
The reaction in question will be carried out in a calorimeter. The volume of the chamber inside is 2.00 L. Experiment starts by evacuating the chamber to 0.00 kPa. Then oxygen gas is filled into the chamber till pressure 200. kPa. Then hydrogen gas is filled into the same chamber until total pressure 400. kPa. The oxygen and hydrogen mixture is ignited by a spark with 3.00 kJ energy. Calculate the total pressure inside the chamber after reaction.
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