the first one is correct, the 2nd is not
try f(4) in your equation, you do not get zero.
I had f(x) = a(x^2+1)(x-4)
then for f(-3)=60
60 = a(10)(-7)
a= -6/7
so f(x) = -6/7(x^2+1)(x-4)
expand it for your answer
Could you please check my answers?
Find an nth degree polynomial function with real coefficients satisfying the given conditions.
1. n=3; 3 and i are zeros; f(2)=20
-I got: f(x)=-4^3+12x^2-4x+12
3.n=3;4 and i zeros;f(-3)=60
-I got:f(x)=6x^3+24x^2+6x+24
1 answer
1 answer