moles glucose = 10g/180.16 = ??
moles CO2 = moles glucose x (6 moles CO2/1 mole glucose) = 6 x moles glucose.
Could someone walk me through this problem?
6CO2 + 6H2O --> C6H12O6 + 6O2
partial pressure of CO2 is .26Torr, temp is 25 celsius, calculate volume of air to prouduce 10g glucose
I keep getting confused with stoichiometry....my thinking: convert 10 g glucose to moles (which I found to be .0556 mol) and then I'll need that because there's a 6:1 mole relationship with CO2..but I'm not completely sure how to use this.
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