you want
(x-12)^3 - 7 = 0
(x-12)^3 = 7
x-12 = ∛7
x = 12 + ∛7
Could someone please explain the steps in finding all the real zeroes
y=(x-12)^3-7
I do not know how
1 answer
y=(x-12)^3-7
I do not know how
1 answer
3 answers
1 answer
1 answer
1 answer