Could someone please explain how to figure this out step by step. I'll give you one of my problems and I'll try to figure out the rest.

Directions: For each situation find the value of x and the measure of the indicated segment.

1. UY=4x-3, YV=x; UV

5 answers

If UY and YV are segments of a straight line, then

UY+YV=UV
4x-3+x=UV

If one knows UV, then one can solve for x.
Do I add 4x+x which equals 5x so would it be 5x-3=UV??
could you check the one i did myself

2. UV=x+6,UY=x-1;YV
UY+UY=YV
x+6-1=YV
Answer: x-5=YV
well, since UV is greater then UY, it means that UV is the longer segment, UY one part of it, and YV the other part.

So UY+YV=UV
then proceed.
So would the answer be x^2+YV=7