If UY and YV are segments of a straight line, then
UY+YV=UV
4x-3+x=UV
If one knows UV, then one can solve for x.
Could someone please explain how to figure this out step by step. I'll give you one of my problems and I'll try to figure out the rest.
Directions: For each situation find the value of x and the measure of the indicated segment.
1. UY=4x-3, YV=x; UV
5 answers
Do I add 4x+x which equals 5x so would it be 5x-3=UV??
could you check the one i did myself
2. UV=x+6,UY=x-1;YV
UY+UY=YV
x+6-1=YV
Answer: x-5=YV
2. UV=x+6,UY=x-1;YV
UY+UY=YV
x+6-1=YV
Answer: x-5=YV
well, since UV is greater then UY, it means that UV is the longer segment, UY one part of it, and YV the other part.
So UY+YV=UV
then proceed.
So UY+YV=UV
then proceed.
So would the answer be x^2+YV=7