First question is correct
for the second, you don't state the points but from "My work", I am guessing the points were
(-3,-1) and (6,-1)
so the slope is (-1 + 1)/(6 + 3) = 0/9 = 0 , not undefined
for the last one: corrections in bold
y=9/10x+9/10;slope;9/10;yintercept;9/10
y=9/10x-9/10;slope;9/10;y-intercept;-9/10
y=-9/10x+9/10;slope;-9/10;yintercept;9/10
y=9/10x-9/10;slope9/10;y-intercept;-9/10
Could someone please check my work.
what is the slope of the line that passes through the given points?(2,12( and (6,11)
-1/4 (my choice)
1/4
4
-4
My work:
11-12/6-2=-1/4
what is the slope of the line that passes through the given points?
undefined( my choice)
0
-2/3
-3/2
My work;
-1-(-1)/-3-6=0/9
Write an equation in slope-intercept form what are the slope and y-intercept?
y=9/10x+9/10;slope;9/10;yintercept;9/10
y=9/10x-9/10;slope;9/10;y-intercept;9/10
y=-9/10x+9/10;slope;9/10;yintercept;9/10
y=9/10x-9/10;slope9/10;y-intercept;-9/10
This one I definitely need help with.
1 answer