1 is ok. 2 and 3 are not.
2. M = mols/L not mols/mL.
M = 0.5mol/0.5L = 1 M
3. % w/w = (mass solute/100 g solution)*100.
Should be [10 g KCl/(90+10)]*100 = [10g KCl/100 g solution]*100 = 10%
Could someone let me know if I answered these questions?
1. How do you classify the liquid pair mineral oil -- H2O, miscible or immiscible? I believe the answer is immiscible because oil and water do not mix.
2. what would be the Molarity of a solution containing 0.5 mole of KBr in 500ML (0.5L) I think the answer is
0.5 mole of KBr/500mL = 0.001M
3. A student made a solution of 10g KCl and 90 g of water, what % solution did he make? I think the answer is 10g of KCL/90g H2O(100) = 11.11% solution.
If I answered these questions incorrectly, I would appreciate it if someone could tell me what I did wrong and tell me how to fix it. Thanking you in advance
1 answer
1 answer