Could someone give me an example of a linear eqution using elimination to solve the systems of equations?

Answer 1

2x + 7y = 16
x - 3y = -5

multiply the 2nd equation by 2

2x + 7y = 16
2x - 6y = -10

subtract the equations to eliminate x:

0x + 13y = 26
y = 2
so,
x = 1

Answer 2

Thanks!!!

Answer 3

What I don't get is that in my book the question is {2x - 3= - 5y and -2y = -3y + 1}. How do I put the question in standard form?

Answer 4

A little help, please!!! :-)

Answer 5

Just move all the x's and y's to one side, and the numbers to the other side:

2x - 3 = -5y
-2x = -3y + 1

becomes

2x + 5y = 3
-2x + 3y = 1

add them together to eliminate the x's

0x + 8y = 4
y = 1/2
so,
x = 1/4

If I misread -2y = -3y + 1 then you can surely fix it and get the expected answer.

Answer 6

In most cases it is best to have the x's and y's on one side, with the constant on the other side

2x - 3 = -5y becomes
2x + 5y = 3

Your other equation probably has a typo, I was expecting an x term instead there are two y terms.
Anyway, get the x's and y's to the left, and the constant to the right.
Then proceed in the way that Steve illustrated above.