Could someone check my work please? Thank you!

(14a^2b)(2ab^2c) = 28a^3b^3c

(a^25)^7 = a^125

6x^6 ∙ 6x^6 = 36^12

(2x^2)^3 = 8x^6

(-2)0 = 1

30x^20/(6x^9 = 5x^11

4x^5 ∙ 6x^6 = 24x^11

(2x^4)^3 = 8x^12

-4^2 = -16

-(193)^0 = -1

(-193)0 = 1

(-5)2 = 25
((6x^7)/(2x^2 ))^2 = 9x^45???????

(-6x&6)(-6x^2x^6) -- I have no idea how to solve this one. HELP PLEASE!

4 answers

(14a^2b)(2ab^2c) = 28a^3b^3c ✔

(a^25)^7 = a^125 ✔

6x^6 ∙ 6x^6 = 36^12 no,
keep the base and add the exponents = 6^12
or multiply the bases and keep the same exponent = 36^6

(2x^2)^3 = 8x^6 ✔

(-2)^0 = 1 ✔

30x^20/(6x^9 = 5x^11 ✔

4x^5 ∙ 6x^6 = 24x^11 ✔

(2x^4)^3 = 8x^12 ✔

-4^2 = -16 ✔

-(193)^0 = -1 ✔

(-193)^0 = 1 ✔

(-5)2 = 25 ✔
((6x^7)/(2x^2 ))^2 = 9x^45??????? NO
= (3x^5)^2
= 9x^10

(-6x&6)(-6x^2x^6) , you meant (-6x^6)(-6x^2x^6)
= 36x^14
=
6x^6 ∙ 6x^6 = 36^12 no,
keep the base and add the exponents = 6^12
or multiply the bases and keep the same exponent = 36^6

Why would this be? I thought I had to multiply the 6 in each and then add the exponents in each?

((6x^7)/(2x^2 ))^2 = 9x^45??????? NO
= (3x^5)^2
= 9x^10

I re-did this one before you responded and got this answer also.

(-6x&6)(-6x^2x^6) , you meant (-6x^6)(-6x^2x^6)
= 36x^14
=
I also re-did this one and got this but with the extra = sign are you saying there is more to simplify because I thought this would be the final answer.

Thanks so much - I'm just trying to make certain I understand this.
6x^6 ∙ 6x^6 = 36^12

Your answer is wrong, should be
36x^12

looks like you missed the x
and for some reason I thought you multiplied the bases of 6 and added the exponents.

In the last question, the last = sign
is just a stray one hanging around, ignore it.
Reiny, thanks but the original problem isn't (-6x^6)(6x^6)

The original problem is (-6x^6)(-6x^2x^6)

So I thought I would have to simplify inside the second parentheses first to make that (-6x^8) by adding the exponents (2 + 6)

Then I have (-6x^6)(-6x^8)

I then multiply -6 x -6 = 36
and then add the exponents to get 36x^14