Could somebody help me I don't understand any of this. Could someone show me or tell me how to work the problems?
1. Find the length of the hypotenuse of a right triangle with the legs of 9cm and 12cm
A.8
B.21
C.15
D.225
2.The length of a hypotenuse of a right triangle is 13cm. The length of one leg is 5cm. Find the length of the other leg.
A.14
B.144
C.8
D.12
3.Which of the triangles decribed in the table are a right triangle?
Triangle | Side 1 | Side 2 | Side3 |
Q | 25 | 20 | 15 |
R | 26 | 20 | 14 |
S | 25 | 20 | 1026 |
T | 25 | 26 | 650 |
Answer choices:
A. (Q)
B. (R)
C.(S)
D.(T)
4.Point E is located at point (-2, 2) and point F is located at (4, -6). What is the distance between point E to F?
A.52 squared
B.28 squared
C.10
D.20 squared
14 answers
9^2 + 12^2 = c^2
81 + 144 = c^2
225 = c^2
sqrt(225) = sqrt (c^2)
c = 15
2. 5^2 +b^2 = 13^2
25 + b^2 = 169
25-25 + b^2 = 169-25
b^2 = 144
b= 12
3. Q
15^2 +20^2 = c^2
225 +400 =c^2
625 = c^2
c = 25
4. Sqrt (4-(-2)^2 + (-6-2)^2))
Sqrt (36 + 64)
= 10
Pythagorean theorem
c = sqrt ( a ^ 2 + b ^ 2 )
c = sqrt ( 9 ^ 2 + 12 ^ 2 )
c = sqrt ( 81 + 144 )
c = sqrt ( 225 )
c = 15
Answer C
2.
Pythagorean theorem
b = sqrt ( c ^ 2 - a ^ 2 )
b = sqrt ( 13 ^ 2 - 5 ^ 2 )
b = sqrt ( 169 - 25 )
b = sqrt ( 144 )
b = 12
Answer D
3.
Pythagorean theorem
c = sqrt ( a ^ 2 + b ^ 2 )
Answer A
becouse :
c = sqrt ( 20 ^ 2 + 15 ^ 2 )
c = sqrt ( 400 + 225 )
c = sqrt ( 625 )
c = 25
4.
The Distance Formula :
d = sqrt [ ( x2 - x1 ) ^ 2 + ( y2 - y1 ) ^ 2 ]
In this case :
x1 = - 2
x2 = 4
y1 = 2
y2 = - 6
d = sqrt [ ( 4 - ( - 2 ) ) ^ 2 + (- 6 - 2 ) ^ 2 ]
d = sqrt [ ( 4 + 2 ) ^ 2 + ( - 8 ) ^ 2 ]
d = sqrt [ 6 ^ 2 + ( - 8 ) ^ 2 ]
d = sqrt ( 36 + 64 )
d = sqrt ( 100 )
d = 10
Answer C
And you should watch the time. You posted at 2:23 am!! ~ This website is set for Eastern (US) time, and most of the tutors are in either Eastern or Central time zones.
2. D
3. A
4. C
5. B
6. A
7. A
8. B
9. Workpad