cot² A/cosec A + 1)²=1-sin A/1+sin A.

1 answer

I noticed that you made a correction from your previous post, but It still would not work.
It should be:

cot² A/(cosec A + 1)²= (1-sin A)/(1+sin A)

notice the important brackets.

LS = cot² A/(cosec A + 1)²
= (cos^2 A/sin^2 A)/(1/sina + 1)^2
= (cos^2 A/sin^2 A)((1 + sinA)^2/sin^2 A)
= (cos^2 A/sin^2 A)*(sin^2 A)/(1 + sinA)^2
= cos^2 A/(1+sinA)^2
= (1-sin^2 A)/(1+sinA)^2
= (1-sinA)(1+sinA)/( (1+sinA)(1+sinA) )
= (1 - sinA)/(1 + sinA)
= RS
Similar Questions
  1. Verify the identity. Show your work.cot2x + csc2x = 2csc2x - 1 1+cosec^2x +cosec^2x Cot^2x+cosec^x= 1+2 cosec^2x Would this be
    1. answers icon 2 answers
  2. 1) Simplification (trigonometric ratios of allied angles)?Simplify : i) [cos^2 (2x180-A). tan^2 (180+A). sec^2 (180-A)] / [
    1. answers icon 1 answer
  3. Someone please help!!!?7. What is 1/cot(x) in terms of sine? This is what I've got so far: sin = 1/csc tan = 1/cot 1+cot2(x) =
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions