cosx sinx -sinx=0
3 answers
i solve it and get 3 answer but in the back of the book, it ony gave 2 answer.
cosx sinx -sinx=0
sinx(cosx - 1) = 0
sinx = 0 or cosx = 1
within 0 ≤ x ≤ 360°
from sinx = 0 , x = 0 , 180° , 360°
from cosx = 1 , x = 0 , 360°
so x = 0 , 180°, 360°
sinx(cosx - 1) = 0
sinx = 0 or cosx = 1
within 0 ≤ x ≤ 360°
from sinx = 0 , x = 0 , 180° , 360°
from cosx = 1 , x = 0 , 360°
so x = 0 , 180°, 360°
Usually both 0 and 360 are not in the domain, so the book probably only lists 0 and 180 as solutions.