Ask a New Question
Search
cosx-sinx=1/4, find cosxsinx
1 answer
(cosx-sinx)^2 = 1/16
cos^2x - 2sinx cosx + sin^2x = 1/16
2sinx cosx = 15/16
sinx cosx = 15/32
Ask a New Question
or
answer this question
.
Similar Questions
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
cosx-sinx=1/4, find cosxsinx
1 answer
If y=3/(sinx+cosx) , find dy/dx
A. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
1 answer
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
0 answers
more similar questions