Cost wants to attend the fall festival at school. The price of admission to the festival is $5.50 and each game costs and addition 75 cents. If Cody has $15.00 to spend at the festival ehch inequality can be used to solve for g, the number of games that he can play, and what is the maximum number of games he can play.

Question

A.5.50+0.75g<=15.00; 12 games
B.5.50+0.75g<=15.00; 13 games
C.0.75 + 5.5g <=15.00; 2 games
D. 0.75 +5.5g <= 15.00; 3 games

Answer 1

To find the correct inequality and the maximum number of games Cody can play, we can set up the equation based on the total amount of money he has.

1. The price of admission is $5.50.
2. The cost per game is $0.75.
3. Cody has a total of $15.00 to spend.

The total cost for the admission and the games can be represented by the following inequality:

\[ 5.50 + 0.75g \leq 15.00 \]

Where \(g\) represents the number of games Cody can play.

Now, we can solve this inequality for \(g\):

1. Subtract $5.50 from both sides:

\[ 0.75g \leq 15.00 - 5.50 \]

\[ 0.75g \leq 9.50 \]

2. Now, divide both sides by $0.75:

\[ g \leq \frac{9.50}{0.75} \]

\[ g \leq 12.6667 \]

Since \(g\) must be a whole number (Cody cannot play a fraction of a game), we round down to the nearest whole number. Therefore, the maximum number of games Cody can play is:

\[ g = 12 \]

Thus, the correct option is:

A. \(5.50 + 0.75g \leq 15.00\); 12 games.