Cos^2(theta)-3csc(theta)+2 divided by csc(theta)-1

4 answers

I hope you mean
(csc^Ø - 3cscØ + 2)/(cscØ - 1)
if so, then

(cscØ - 1)(cscØ - 2)/(cscØ-1)
= cscØ - 2
It's Cos^2(theta) is that the same as csc^(theta)?
no
csc^(theta) is meaningless notation. Theta is never an exponent (although it could be). You would still need to specify an angle for which you are taking the cosecant.

cos^2(theta) means the same thing as
[cos(theta)]^2
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