To transform the function \( f(x) \) to \( f(3x-2) + 1 \) and complete the table, we start with the expression \( 3x - 2 \) and apply the operations in the correct order.
Function Transformation
We are transforming: \[ f(x) \quad \text{to} \quad f(3x-2) + 1 \]
Order of Operations Steps
Let's break down how we can evaluate this expression step by step:
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Step 1: Plug in \( x \) into the function expression.
- Expression: \( 3(3x - 2) + 1 \)
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Step 2: Distribute the 3.
- Expression: \( 9x - 6 + 1 \)
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Step 3: Combine like terms (add -6 and 1).
- Expression: \( 9x - 5 \)
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Step 4: Now we have \( f(3x - 2) + 1 \) evaluated to \( 9x - 5 \).
- Expression: Resulting function is \( 9x - 5 \)
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Step 5: Final form of the function (if needed for a specific value).
- Expression could evaluate at a specific x-value if necessary.
Filling in the Table
| Step | Expression | Result | |--------|-----------------------------------|-----------| | Step 1 | \( 3(3x - 2) + 1 \) | | | Step 2 | \( 9x - 6 + 1 \) | | | Step 3 | \( 9x - 5 \) | | | Step 4 | (Function transformation complete) | | | Step 5 | (Final result, if applicable) | |
Applying given options to find results
Now, let's evaluate the actual numerical values. If we want specific results, we'd plug in a value for \( x \) -- for example, if \( x = 1 \):
- \( 3(3(1) - 2) + 1 \) would become:
- \( 3(3 - 2) + 1 \) = \( 3(1) + 1 \) = 3 + 1 = 4.
So:
- Step 1 Expression: \( 3(3x-2) + 1 \)
- Result for \( x = 1 \): \( 4 \)
You can apply any value you choose for \( x \) in this manner. For the remaining table cells, you can derive results based on whatever values you wish to use for \( x \).
Please let me know if you need more specific values or any other assistance!