To find the surface area of the tetrahedron, you need to find the area of each of the four triangular faces and then add them together.
The formula for the area of an equilateral triangle is:
\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]
In this case, the base of the triangle is 5 inches and the height is 4.33 inches. So, plugging these values into the formula:
\[ A = \frac{1}{2} \times 5 \times 4.33 = \frac{5}{2} \times 4.33 = 2.5 \times 4.33 = 10.825 \text{ in}^2 \]
Since there are four faces, you need to multiply this area by 4 to get the total surface area of the tetrahedron:
\[ \text{Total Surface Area} = 4 \times 10.825 = 43.3 \text{ in}^2 \]
Therefore, the surface area of the tetrahedron is 43.3 square inches.
Corey is trying to find the surface area of a tetrahedron They sketch a net of the tetrahedron on their paper. The net shows four congruent, equilateral triangle, each with base of 5 in and a high of approximately 4.33 in. What should Corey do next? Help Corey find the surface area of the tetrahedron
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