copper metal reacts with nitric acid. assume that the reaction is 3Cu(s) + 8HNO3(aq) ——> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l). if 5.58 grams of Cu(NO3)2 is obtained, how many grams of nitrogen monoxide would have formed

Answer 1

how many moles of Cu(NO3)2 in 5.58g?

2 moles 2NO are produced for every 3 moles Cu(NO3)2.