Convert to Logarithmic equations.

Question

10. 4^-3 =1/64 I have the answer as log4 1/64 =-3

11. 144^1/2 =12 I have the answer as
log 144^12 =1/2

Are these answers right?

Answer 1

I must admit I'm not sure what you are doing but if I converted
4^-3 = 1/64 to a log equation, I would write
-3*log 4 = log(1/64).
I don't know what your answer means as
log4 1/64 = -3 since the 1/64 is just dangling out there by itself with nothing to tell me what you want to do with it.

and for 144^1/2 = 12 I would write
1/2*log 144 = log 12

By the way, when you post problems, be careful that the NUMBER of the problem doesn't run into the problem. For example, the first problem I kept reading as 10.4^-3 = 1/64

Answer 2

Thanks.

Answer 3

I have a question the formula that I used was b^y=x means that logbx=y
is this the correct formula?
so using that formula I got the following.
4^-3 =1/64 I have the answer as log4 1/64 =-3

144^1/2 =12 I have the answer as
log 144^12 =1/2

Answer 4

yes, you are right

if b^y = x then log_bx = y

that is the basic definition of a logarithm

Answer 5

So then are these answers right?
10.) 4^-3 =1/64 I have the answer as log4 1/64 =-3

11.) 144^1/2 =12 I have the answer as
log 144^12 =1/2

Answer 6

I don't like the way you wrote it as
log 144^12 =1/2
the ^ we use as an exponent sign, there is no exponent involved
should have been

log₁₄₄ 12 = 1/2