Convert the quadratic y=(x+4)2−5y=(x+4)2−5 from vertex form to standard form.(1 point)

Answer 1

To convert the quadratic equation \( y = (x + 4)^2 - 5 \) from vertex form to standard form, we need to expand the equation.

1. Start with the vertex form: \[ y = (x + 4)^2 - 5 \]

2. Expand \( (x + 4)^2 \): \[ (x + 4)^2 = x^2 + 8x + 16 \]

3. Substitute this back into the equation: \[ y = x^2 + 8x + 16 - 5 \]

4. Combine the constant terms: \[ y = x^2 + 8x + 11 \]

Thus, the standard form of the quadratic is: \[ y = x^2 + 8x + 11 \]