Convert the quadratic y = 2(x−5)2 − 10

from vertex form to standard form.(2 points)
The standard form of the quadratic is y=
x2+
x+
.
Remaining Attempts : 3

1 answer

To convert the quadratic equation from vertex form to standard form, we start with the given vertex form:

\[ y = 2(x - 5)^2 - 10 \]

Step 1: Expand the vertex form

First, we need to expand \((x - 5)^2\):

\[ (x - 5)^2 = x^2 - 10x + 25 \]

Step 2: Substitute back into the equation

Now, substitute this expansion back into the original equation:

\[ y = 2(x^2 - 10x + 25) - 10 \]

Step 3: Distribute the 2

Next, distribute the 2:

\[ y = 2x^2 - 20x + 50 - 10 \]

Step 4: Combine like terms

Now, combine the constants:

\[ y = 2x^2 - 20x + 40 \]

Result

Now we can write the standard form of the quadratic, which is:

\[ y = 2x^2 - 20x + 40 \]

Thus, we have:

  • The standard form is \(y = 2x^2 + (-20)x + 40\).

So the answer is:

  • \(y = 2x^2 - 20x + 40\).