Convert the equation from vertex form to standard form y=−4(x+5)2−3

Responses

y=−4x^2−25x−3

y=16x^2+160x+412

y=−4x^2−40x−103

y=16x^2+160x+397

1 answer

To convert the equation \( y = -4(x + 5)^2 - 3 \) from vertex form to standard form, we will first expand the equation.

  1. Start with the vertex form: \[ y = -4(x + 5)^2 - 3 \]

  2. Expand \( (x + 5)^2 \): \[ (x + 5)^2 = x^2 + 10x + 25 \]

  3. Substitute this back into the equation: \[ y = -4(x^2 + 10x + 25) - 3 \]

  4. Distribute the \(-4\): \[ y = -4x^2 - 40x - 100 - 3 \]

  5. Combine the constant terms: \[ y = -4x^2 - 40x - 103 \]

Thus, the standard form of the equation is: \[ \boxed{y = -4x^2 - 40x - 103} \]

This matches one of the given responses.