we know r^2 = x^2 + y^2 and x/r =cosØ, y/r = sinØ
given:
rsecØ = 3
r = 3/secØ
r = 3cosØ
r = 3(x/r)
r^2 = 3x
x^2 + y^2 = 3x , rewrite it any way you want.
the last one is done the same way
2nd :
I will assume you r = 5/(cosØ-2sinØ
r = 5/(x/r - 2y/r)
r = 5/((x-2y)/r)
r = 5 * r/(x - 2y)
1 = 5/(x-2y)
x-2y = 5
convert from polar form into rectangular form. type the equation in rectangular form (simplified):
1) rsecθ = 3
2) r=5/cosθ-2sinθ
3) r=5cscθ
2 answers
5. Find the Cartesian form of the equation, r3 = 3r cosØ.
1 answer