To convert the equation \( y + 2 = -3(x - 5) \) into slope-intercept form (which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept), follow these steps:
-
Distribute \(-3\) on the right side: \[ y + 2 = -3x + 15 \]
-
Subtract \(2\) from both sides to solve for \(y\): \[ y = -3x + 15 - 2 \] \[ y = -3x + 13 \]
Now the equation is in slope-intercept form:
\[ y = -3x + 13 \]
Here, the slope \(m\) is \(-3\) and the y-intercept \(b\) is \(13\).
1 answer