To convert the equation \(8x + y = 4\) into slope-intercept form, which is \(y = mx + b\) (where \(m\) is the slope and \(b\) is the y-intercept), we need to isolate \(y\).
Starting with the original equation:
\[ 8x + y = 4 \]
Subtract \(8x\) from both sides:
\[ y = -8x + 4 \]
Now, the equation is in slope-intercept form. The slope \(m\) is \(-8\) and the y-intercept \(b\) is \(4\).
So, the equation in slope-intercept form is:
\[ y = -8x + 4 \]