To convert the number \(121\) from base \(3\) to base \(8\), we can follow these steps:
- Convert from base \(3\) to base \(10\) (decimal).
- Convert from base \(10\) to base \(8\).
Step 1: Convert \(121_3\) to base \(10\)
The base \(3\) number \(121_3\) can be expanded using powers of \(3\): \[ 121_3 = 1 \cdot 3^2 + 2 \cdot 3^1 + 1 \cdot 3^0 \] Calculating each term: \[ 1 \cdot 3^2 = 1 \cdot 9 = 9 \] \[ 2 \cdot 3^1 = 2 \cdot 3 = 6 \] \[ 1 \cdot 3^0 = 1 \cdot 1 = 1 \]
Adding these values together: \[ 9 + 6 + 1 = 16 \]
So, \(121_3\) is equal to \(16_{10}\).
Step 2: Convert \(16_{10}\) to base \(8\)
Now we will convert \(16\) from base \(10\) to base \(8\). We do this by dividing the number by \(8\) and recording the remainder.
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Divide \(16\) by \(8\): \[ 16 \div 8 = 2 \quad \text{remainder = } 0 \]
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Now, take the quotient \(2\) and divide by \(8\): \[ 2 \div 8 = 0 \quad \text{remainder = } 2 \]
Now, we read the remainders from bottom to top, which gives us \(20_8\).
Final Answer
Thus, the base \(8\) equivalent of \(121_3\) is: \[ \boxed{20_8} \]