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Original Question
Convert 101 base 3 to 8Asked by Rahamat Bello Bakwai
Convert 110 base 3 to 8
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Answered by
GPT-4o mini
To convert the number \(110\) from base \(3\) to base \(8\), we will first convert it to base \(10\) and then from base \(10\) to base \(8\).
### Step 1: Convert from base \(3\) to base \(10\)
The base \(3\) number \(110\) can be expanded as follows:
\[
1 \times 3^2 + 1 \times 3^1 + 0 \times 3^0
\]
Calculating each term:
- \(1 \times 3^2 = 1 \times 9 = 9\)
- \(1 \times 3^1 = 1 \times 3 = 3\)
- \(0 \times 3^0 = 0 \times 1 = 0\)
Now, adding these values together:
\[
9 + 3 + 0 = 12
\]
So, \(110_3\) is equal to \(12_{10}\).
### Step 2: Convert from base \(10\) to base \(8\)
Now, we convert \(12_{10}\) to base \(8\).
To do this, we divide the number by \(8\) and keep track of the remainders:
1. \(12 \div 8 = 1\) with a remainder of \(4\)
2. \(1 \div 8 = 0\) with a remainder of \(1\)
Now, we read the remainders from bottom to top, which gives us \(14\) in base \(8\).
Thus, \(12_{10}\) is equal to \(14_8\).
### Conclusion
Therefore, the base \(3\) number \(110\) is equal to \(14\) in base \(8\):
\[
110_3 = 14_8
\]
### Step 1: Convert from base \(3\) to base \(10\)
The base \(3\) number \(110\) can be expanded as follows:
\[
1 \times 3^2 + 1 \times 3^1 + 0 \times 3^0
\]
Calculating each term:
- \(1 \times 3^2 = 1 \times 9 = 9\)
- \(1 \times 3^1 = 1 \times 3 = 3\)
- \(0 \times 3^0 = 0 \times 1 = 0\)
Now, adding these values together:
\[
9 + 3 + 0 = 12
\]
So, \(110_3\) is equal to \(12_{10}\).
### Step 2: Convert from base \(10\) to base \(8\)
Now, we convert \(12_{10}\) to base \(8\).
To do this, we divide the number by \(8\) and keep track of the remainders:
1. \(12 \div 8 = 1\) with a remainder of \(4\)
2. \(1 \div 8 = 0\) with a remainder of \(1\)
Now, we read the remainders from bottom to top, which gives us \(14\) in base \(8\).
Thus, \(12_{10}\) is equal to \(14_8\).
### Conclusion
Therefore, the base \(3\) number \(110\) is equal to \(14\) in base \(8\):
\[
110_3 = 14_8
\]
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