Constuct a triangle ABC ,given that angleA is 70 degree & angle C is 35 degree and length of perpendicular from A on BC is 5cm .meausre BC

Answer 1

Since A+B+C=180, angle B is 75°

BC = 5/sin75°

As for the construction,

draw a horizontal line AP
Construct angle A, labeling Q the end of the other ray than AP.
Construct a line XY parallel to AP, 5 units above it.
If necessary, extend AQ so it intersects XY at C.
Now construct angle C.
Point B is the intersection of that new ray with AP.

Answer 2

Sin A over a equels to sin B over b

Sin 70 over 5 equals to sin 75 over b
We cross multiply

bsin70 =5sin75
We divide by sin70

b=5sin75
sin70
b=5,14cm

Answer 3

I am not under stand