We have AD perpendicular to BC.
So triangle ABD is right-angled at D.
AB=7, BD=3, therefore by Pythagoras theorem,
AD=√(AB²-BD²)
=√(7²-3²)
=√40
Construct triangle ABD with the given dimensions. Extend BD to C such that BC=13. Join A and C to complete triangle ABC.
Construction of triangle ABC IN which AB-7cm BC-13cm and BD-3cm where AD perpendicular BC
1 answer
3 answers