construct triangle PQR in which pq is equal to 5.5cm , qr =8.5cm , and pqr =75°. construct M, the mid point of PR , measure QM
2 answers
We cannot construct a triangle on these posts.
draw PQ of length 5.5
With Q as center draw a circle of radius 8.5
Construct the angle PQR and extend the ray to where it meets the circle. That is R.
Draw PR and construct its perpendicular bisector, which will meet it at M.
Measure QM
I assume you know how to bisect an angle and construct a perpendicular bisector. 75° is 90-15 or 90 - 30°/2
just to check,
QR^2 = (5.5^2 + 8.5^2 - 2*5.5*8.5cos75°) = 78.3
QR = 8.8487
QM = QR/2 = 4.42
With Q as center draw a circle of radius 8.5
Construct the angle PQR and extend the ray to where it meets the circle. That is R.
Draw PR and construct its perpendicular bisector, which will meet it at M.
Measure QM
I assume you know how to bisect an angle and construct a perpendicular bisector. 75° is 90-15 or 90 - 30°/2
just to check,
QR^2 = (5.5^2 + 8.5^2 - 2*5.5*8.5cos75°) = 78.3
QR = 8.8487
QM = QR/2 = 4.42
1 answer