Construct a quadrilateral PQRS sue that PQ = 8cm , QPS = 105 ° , measure of angle PQS = 30° ,PR = 9cm RS = RQ

Answer 1

I need the answer

Answer 2

I assume you can construct a right angle, a 60° angle, and can bisect an angle. If not, see online for examples.
draw PQ of length 8
construct QPS (90° + 60°/4)
construct PQS (60°/2) and extend the ray QS as needed to where it meets ray PS at S.
with P as center, draw an arc of radius 9, to where it will intersect QS
R will lie on the perpendicular bisector of QS, where it intersects the arc.

Answer 3

Please do this.