Huh? You already said that |AB|=4cm
To construct the figure,
bisect a 60° angle to get angle A.
Mark B where an arc of radius 4 intersects one side of angle A.
C lies on a circle CB of radius 5 with center at B.
D lies on a circle CA of radius 5 with center at A.
So, CD is a segment joining any two suitable points on CA and CB
Construct a quadrilateral ABCD such that /AB /=4cm, /BC /,=5cm, /AD /=3.5cm and CAB=30°.measure /AB/
2 answers
oops. CA has radius 3.5