Have you changed compounds. Your earlier question concerned 4-aminoethyl benzoate. Straight benzoic acid would form a salt since it is an acid reacting with a base, NaOH.
ArCOOH + NaOH ==> H2O + ArCOONa where Ar is the benzene ring.
c). If HCl is added to the tube, HCl neutralizes the NaOH and reprecipirates the benzoic acid.
Considering the tube wherein NaOH (1 M) was added to benzoic acid.
a) what reaction would occur in the tube?
b) write a balance equation that supports your explanation above?
c) describe what would happen if u added HCL (6 M) to the same tube?
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