Considering the neutralization reaction when nitric acid reacts with solid iron(II)carbonate. What is the minimum volume of 2.00 M HNO3 necessary to react completely with 1.06 kg of solid iron(II) carbonate, FeCO3 ?

Answer 1

FeCO3 + 2HNO3 ==> Fe(NO3)2 + H2O + CO2
1.06 kg Fe = 1060 grams.
mols FeCO3 = grams/molar mass.
Using the coefficients in the balanced equation, convert mols FeCO3 to mols HNO3.
Then mols HNO3 = M x L. You know mols and M, solve for L and convert to whatever unit (mL for example) if needed.