Asked by Jack Donald
Considering the following system of linear equations:
−9 x−6 y = 0
−7 x+5 y = −87
What are values of p and q such that the system below is equivalent to the one above.
px-10y = 78
7x+qy = 105
−9 x−6 y = 0
−7 x+5 y = −87
What are values of p and q such that the system below is equivalent to the one above.
px-10y = 78
7x+qy = 105
Answers
Answered by
oobleck
-10/-6 = 5/3 so multiply the equation by 5/3 to get
-15x-10y = 0
similarly, just multiply the 2nd equation by -1 to get
7x-5y = 87
-15x-10y = 0
similarly, just multiply the 2nd equation by -1 to get
7x-5y = 87
Answered by
Jack Donald
Hi,
Are you able to explain a bit more about what you did?
Sorry for the confusion.
Are you able to explain a bit more about what you did?
Sorry for the confusion.
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