Considering the following system of linear equations:

Question

−9 x−6 y = 0
−7 x+5 y = −87

What are values of p and q such that the system below is equivalent to the one above.

px-10y = 78
7x+qy = 105

Answer 1

-10/-6 = 5/3 so multiply the equation by 5/3 to get
-15x-10y = 0
similarly, just multiply the 2nd equation by -1 to get
7x-5y = 87

Answer 2

Hi,

Are you able to explain a bit more about what you did?
Sorry for the confusion.