Consider two vectors F~

Question

1 and F~
2 with magnitude
F1 = 61 N and F2 = 63 N
and where θ1 = 98 ◦
and θ2 = 50 ◦The
angles are measured from the positive x axis
with the counter-clockwise angular direction
as positive.
What is the magnitude of the resultant vector F where F = F1+F2

Answer 1

F = 61[98o] + 63[50o].

X = 61*Cos98 + 63*Cos50 = -8.49 + 40.50
= 32.0 N.
Y = 61*sin98 + 63*sin50 = 60.41 + 48.26
= 108.7 N.

F = sqrt(X^2+Y^2).