Explanation:
For Bus 1, we can use the given function f(t) = 64t to find how far it travels in 6 hours: f(6) = 64(6) = 384 miles.
For Bus 2, we know that it traveled 124 miles in the first 2 hours, leaving 4 more hours to travel. Since its speed is constant, we can use the formula distance = speed × time. Let's call the speed of Bus 2 "s". Then, in the remaining 4 hours, Bus 2 travels:
distance = speed × time = s × 4
We don't have enough information to find s, so we can't calculate the exact distance traveled by Bus 2. However, we can make a general statement: if Bus 2's constant speed is greater than 31 miles per hour (which would make its total distance traveled greater than 124 + 31 × 4 = 248 miles), then Bus 2 will travel farther than Bus 1. Otherwise, Bus 1 will travel farther.
Since we don't know the exact speed of Bus 2, the correct answer is "none of these".
Consider two buses departing at the same time. For every hour t, Bus 1 will have traveled f(t) = 64t miles, while Bus 2 travels at a constant speed and goes 124 miles in the first 2 hours. At 6 hours, which statement is true?
Responses
Bus 1 will travel farther than Bus 2.
Bus 1 will travel farther than Bus 2.
none of these
none of these
Bus 2 will travel farther than Bus 1
Bus 2 will travel farther than Bus 1
Bus 1 and Bus 2 will travel the same distance.
Bus 1 and Bus 2 will travel the same distance.
2 answers
AAAaannndd the bot gets it wrong yet again!
Bus 124/2 = 62 mi/hr, so it is slower than Bus 1.
Bus 124/2 = 62 mi/hr, so it is slower than Bus 1.