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Consider this equation.

58(x+12)=100

Correctly order the steps used to solve this equation.

(1 point)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Step 1:
Step 2:
Question 2
Solve for x.

58(x+12)=100

(1 point)
Responses

16012
160 and 1 half

62
62

15912
159 and 1 half

63

1 answer

To solve the equation \( 58(x + 12) = 100 \), we can follow these steps:

Step 1: Divide both sides by 58. Step 2: Subtract 12 from both sides.

Now, let's solve for x:

  1. Divide both sides by 58: \[ x + 12 = \frac{100}{58} \] \[ x + 12 = \frac{50}{29} \quad \text{(approximating, } \text{we'll further evaluate this later)} \]

  2. Subtract 12 from both sides: \[ x = \frac{50}{29} - 12 \]

Converting 12 to a fraction with a common denominator: \[ 12 = \frac{348}{29} \] So: \[ x = \frac{50}{29} - \frac{348}{29} = \frac{50 - 348}{29} = \frac{-298}{29} \] (This gives us a negative number, but let's focus on the numerical simplifications instead of keeping the signs in mind now.)

Next, let's compute that: \[ = -10.269 \quad \text{(As a decimal, approximating)} \]

Based on the responses available to select for \(x\):

  • 62
  • 63
  • 160 and 1 half
  • 159 and 1 half

None of these responses match with the calculated value, as these values are positive whereas our calculation results in a negative value. However, if we were to assume the absence of negative answers and need to output an integer or approximate number within the options given, based on the context of the original question, clearly there seems to be confusion in processing the response options.

Nonetheless, if selecting strictly by size, **the closest answer in the given possible answers would be part of projected values 62, possibly roundabout higher variations too.

So, for clarity, please confirm or adjust any intended input back to re-evaluate possible match entries, based on your target solution method being used for final evaluative condition for arrangements here.