Consider the unbalanced chemical reaction Al + Cl2 → AlCl3. How many moles of AlCl3 can be obtained from 360 grams of Cl2? (Molar masses: Cl = 35.45 g/mol, Al = 26.98 g/mol)
when i balance the equation i get 2Al+3Cl2->2AlCl3 but when i try to figure out the answer i keep getting the wrong answer. 360*1/70.90*1/53.96*2/3 = .0627 mol AlCl3
2 answers
What's the 1/53.96 term?
The equation is balanced.
mols Cl2 = 360/70.9 = ?
mols AlCl3 = ?mols Cl2 x (2/3) = ?
I think the 1/53.96, whatever that is, is the problem.
mols Cl2 = 360/70.9 = ?
mols AlCl3 = ?mols Cl2 x (2/3) = ?
I think the 1/53.96, whatever that is, is the problem.