by law of cosines,
c^2 = a^2 + b^2 - 2ab cosC
Now, having a,b,c and C, use the law of since to get A,B.
sinA/a = sinB/b = sinC/c
Consider the triangle ABC. Suppose that C=69 degrees, a=45 and b= 9 Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth. List all solutions
A=
B=
c=
1 answer