LOL, well I will assume A on table and B falling free
2.94 = mu (4.91)
mu about 0.6
Consider the system shown in the figure. Block A has weight 4.91 N and block B has weight 2.94 N. Once block B is set into downward motion, it descends at a constant speed. Assume that the mass and friction of the pulley are negligible.
Whats the coefficient of kinetic friction mu between block A and the table top?
2 answers
0.6