The 13 is just a scale factor, and has no bearing.
You know that
∞
∑ 1/10^n = 0.11111111 = 1/9
n=1
Consider the series
∑ ∞ n=1
(13/10^n)
Determine whether the series converges, and if it converges, determine its value.
Converges (y/n):
1 answer