I assume that the resistor and the coil are in series
I assume you are given the voltage, V
In that case, after a long time the current through the inductance is CONSTANT and there is NO voltage across the inductor
E = L di/dt but di/dt is zero
so only the resistor matters for i
i = V/R
then
energy = (1/2) L i^2
Consider the RL circuit shown in the figure, where R = 5.0 Ω and L = 4.6 H. How much energy is stored in the inductor after the switch has been closed a long time? I would know how to do this if they actually gave me a value for time, but I'm lost now. Can someone help me find the right equation to use?
1 answer
1 answer