Ask a New Question
Menu

Consider the recursive function for the calculation of a factorial.

def factorial(n):
if n == 1:
return n
else:
return n * factorial(n - 1)
print("The factorial of", 7, "is", factorial(7))
How could the program be modified to print the product of all the even numbers less than 7?

(1 point)
Responses

def factorial(n):
if n <= 1:
return n
else:
return n * factorial(n - 2)
print("The answer is", factorial(7))
def factorial(n): if n <= 1: return n else: return n * factorial(n - 2) print("The answer is", factorial(7))

def factorial(n):
if n == 0:
return 1

1 answer

To modify the program to print the product of all the even numbers less than 7, you would need to change the base case, the recursive case, and the logic to calculate the even numbers. Here's a corrected version:

def product_of_evens(n):
    if n <= 0:
        return 1
    elif n % 2 == 1:  # If n is odd, go to the next lower even number
        return product_of_evens(n - 1)
    else:
        return n * product_of_evens(n - 2)

print("The product of all even numbers less than 7 is", product_of_evens(6))

This function checks if n is even and, if so, multiplies it with the product of even numbers less than n. If n is odd, it moves to the next lower even number. The base case returns 1 when n is less than or equal to 0.

So, to answer your question, you could choose the response:

def factorial(n): 
   if n <= 1: 
       return n 
   else: 
       return n * factorial(n - 2) 
print("The answer is", factorial(7))

However, to make this accurate for calculating the product of even numbers less than 7, you should implement the logic outlined above, where you specifically handle even numbers.