Consider the reaction of 14.20ml of 0.141 M H3PO4 and 0.0521 M Ba(OH)2.
2H3PO4 + 3Ba(OH)2 ->Ba3(PO4)2 + 6HOH
What volume of Ba(OH)2 is required to completely react with the H3PO4?
2H3PO4 + 3Ba(OH)2 ->Ba3(PO4)2 + 6HOH
What volume of Ba(OH)2 is required to completely react with the H3PO4?