The reaction is exothermic and you know that because the temperature of the water increased.
q = 6795 J for 0.85 mol; therefore,
q = 6795/0.85 = dH = ?
Remember to add a - sign since this is exothermic. Also remember to convert from J to kJ.
Consider the reaction:
M + 2HCl �¨ MCl2 + H2
When 0.85 mol of the metal, M, reacted with an aqueous HCl solution (the HCl is in excess), the temperature of the solution rose because the reaction produced 6795 J of heat. What is ∆H in kJ per mol of M for this reaction? (Hint: Is this reaction exothermic or endothermic?)
3 answers
-7.99
4.7
2 answers